As we have already seen in the previous post to swap two numbers without using the third variable and using the bitwise operator.👇

https://www.javaoneworld.com/2020/03/swap-two-numbers-using-bitwise-operator.html

As I already mentioned that bitwise operators are always computational fast than any mathematical operators.

Why bitwise operators are computational fast than Mathematical operators 👈

so using a bitwise operator instead of a mathematical operator is always a good approach.

Here we are using **&** operator to find that number is Odd or Even.

public class JavaOneWorld { public static void main(String args[]) { int x= 7;
}} |

**The idea behind using the & operator !!!!!**

As we already know binary works only on 1 and 0.

and a number is either odd or even,

so if a number is even then the last bit of that number must be 0 and if odd then the last bit must be 1.

i.e.-

5 odd

101 last bit is 1.

4 even

100 last bit is 0.

so here we have to use this property to find out the odd/even.

if we & 1 in any binary number it will result ---

1 --- if the given number's last bit will 1 (means number is odd)

0 --- if the given number's last bit will 0 (means number is even)

7 -- odd 111& 1-------------- 0014 -- even 100& 1-------------- 000 |

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Happy Coding !!!!!!!!!!!👍👍👍👍👍

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